The sum of numerator and denominator of a fraction is 8?if 3 is added to both numerator nd denominator the fraction becomes 3/4..find the fraction???
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let the numerator = x
denominator =8-x
the fraction =x/8-x ------(1)
if 3 is added to both the fraction=3/4
(x+3)/(8-x+3)=3/4
(x+3)/(11-x)=3/4
4(x+3)=3(11-x)
4x+12=33-3x
4x+3x=33-12
7x= 21
x=21/7
x=3
plug the x=3 in (1)
required fraction =x/(8-x)
=3/(8-3)
=3/5
denominator =8-x
the fraction =x/8-x ------(1)
if 3 is added to both the fraction=3/4
(x+3)/(8-x+3)=3/4
(x+3)/(11-x)=3/4
4(x+3)=3(11-x)
4x+12=33-3x
4x+3x=33-12
7x= 21
x=21/7
x=3
plug the x=3 in (1)
required fraction =x/(8-x)
=3/(8-3)
=3/5
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