Question

the sum of numerator and denominator of a fraction is Greater by 1 than thrice the numerator if the numerator is decreased by 1 then the fraction reduced to 1/2 find the fraction

Answer 1

Answer:

Step-by-step explanation:

Let the numerator be x and deninator be y

x + y = 3 (x)

x + y = 3x + 1

y = 3x + 1 - x

y = 2x + 1

x/y = x/2x + 1

x - 1/y = x/y - 1/2

x - 1/2x + 1 = x/2x + 1 - 1/2

x - 1/2x + 1 = x - 1/2x - 1

Cross multiplication

(x - 1)(2x - 1) = (x- 1)(2x + 1)

(x - 1) on both side get cancelled

2x - 1 = 2x + 1

X = 0

Answer 2

Seems like that is '1/3  not 1/2'

Answer:

4/9

Step-by-step explanation:

et the numerator be 'x' and denominator be 'y'. Thus, fraction be x/y.

Sum of x and y = 1 + 3x

            x + y = 1 + 3x

                  y = 1 + 2x  

If the numerator is decreased by 1, fraction becomes 1/3.

⇒ (x - 1)/y = 1/3

⇒ (x - 1)/(1 + 2x) = 1/3

⇒ 3(x - 1) = 1 + 2x

⇒ 3x - 3 = 1 + 2x

⇒ 3x - 2x = 4       ⇒ x = 4

  thus, y = 1 + 2x = 1 + 2(4) = 9

∴ Fraction = x/y = 4/9