Question

the sum of numerator and denominator of afraction is 8 if 3 is added to both numerator and denominator the fraction becomes 3/4 find the fraction ​

Answer 1

Step-by-step explanation:

let the numerator be - x denominator be- y

x+y=8,x=y-8

x+3/y+3=3/4

4x+12=3y+9

4(8-y)+12-3y-3=0

32+3-7y=0

y=5

x=3

Answer 2

Let, the numberator be x

the denominator be 8-x

ATP

$\frac{x + 3}{11 - x} = \frac{3}{4} \\ = ) \: 4(x + 3) = 3(11 - x) \\ = ) \: 4x + 12 = 33 - 3x \\ = ) \: 4x + 3x = 33 - 12 \\ = ) \: 7x = 21 \\ = ) \: x = \frac{21}{7} = 3$

Numerator = 3

Denominator = (8-3) = 5

Ans:- Fraction is ⅗