the sum of numerator and denominator of fraction is 4 more than twice the numerator . if numerator and denominator are increased by 3,they are in ratio 2:3 .determine the fraction
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Here is your answer,
Let the numerator be x and denominator be y.
A/Q x + y = 4 + 2x → - x + y = 4 ... (1)
multiplying each term by 2, 2x-2y= -8 .... (2)
Also, (x+3) / (y+3) = 2 / 3 → 3x - 2y = -3 ........ (3)
Subtracting (2) from (3) → x = 5 and by putting this in (1) we can get y=9. Hence, the fraction is 5 / 9
Hope it helps you!
Here is your answer,
Let the numerator be x and denominator be y.
A/Q x + y = 4 + 2x → - x + y = 4 ... (1)
multiplying each term by 2, 2x-2y= -8 .... (2)
Also, (x+3) / (y+3) = 2 / 3 → 3x - 2y = -3 ........ (3)
Subtracting (2) from (3) → x = 5 and by putting this in (1) we can get y=9. Hence, the fraction is 5 / 9
Hope it helps you!
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hai mere pas answer
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