Question

The sum of numerator and denominator of fraction is greater by 1 than thrice the numerator.if the numerator is decreased by 1 then the fraction reduced to 1/3. find the fraction​

Answer 1

Answer:

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Step-by-step explanation:

so let the required fraction be x/y

wherein numerator is x and denominator is y

so according to first condition

x+y=3x+1

so y=2x+1 (1)

according to the second condition

x-1/y=1/3 (2)

so substitute value of y in (2)

we get

x-1/2x+1=1/3

so 3(x-1)=2x+1

so 3x-3=2x+1

ie x=4

substitute value of x in any of two equations

we get y=9

thus our assumed fraction=x/y

=4/9

hence required fraction is 4/9