The sum of of the digits of a two digit no. is 9. if 27 is added to it, the digits of no. get reversed. the number is
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Let the tens place digit be a
And Unit place digit be b
According to first condition,
a +b = 9 ----------(1)
According to second condition,
10a + b + 27 = 10b + a
=> 10a + b - 10b - a = - 27
=> 9a - 9b = - 27
=> a - b = - 3 --------(2)
On Adding equation 1 and 2, we get
2a = 6
=> a = 3
Now,
On Substituting the value of a in equation (1) , we get
3 + b = 9
=> b = 6
Required number = 10a + b
= 10 × 3 + 6
= 30 +6
= 36
And Unit place digit be b
According to first condition,
a +b = 9 ----------(1)
According to second condition,
10a + b + 27 = 10b + a
=> 10a + b - 10b - a = - 27
=> 9a - 9b = - 27
=> a - b = - 3 --------(2)
On Adding equation 1 and 2, we get
2a = 6
=> a = 3
Now,
On Substituting the value of a in equation (1) , we get
3 + b = 9
=> b = 6
Required number = 10a + b
= 10 × 3 + 6
= 30 +6
= 36
Answered by
3
hope this may helps you≥3≤
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