Question

The sum of one-eighth, one-twelfth, and one-twentieth parts of a number is 31, find the
number​

Answer 1

Answer:

120

Step-by-step explanation:

Sum of one-eighth,one-twelfth and one-twentieth parts is 31. Hence the required number is 120.

Request:

plz Answer my previous question

Answer 2

$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

The sum of one-eighth, one-twelfth, and one-twentieth parts of a number is 31.

$\underline \mathbb{TO \: FIND:-}$

The unknown number.

$\underline \mathbb{ASSUMPTION:-}$

Let, the number be x.

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

$\frac{1}{8} of \: x + \frac{1}{12} of \: x + \frac{1}{20} of \: x = 31 \\ \\ \implies \: \frac{x}{8} + \frac{x}{12} + \frac{x}{20} = 31\\ \\ \implies \frac{15x + 10x + 6x}{120} = 31 \\ \\ \implies \: \frac{31x}{120} = 31\\ \\ \implies \:x = \frac{ 120 \times \cancel{31}}{ \cancel{31}} \\ \\ \implies \:x \: = 120$

$\underline \mathbb{ANSWER:-}$

The number is 120.