The sum of one-half, one-third and one-fourth of a number exceeds the number by 12. The number is
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0
Answer:
........................
Answered by
2
Answer:
144
Step-by-step explanation:
Let the number be y
As per the question
(1/2)y + (1/3)y + (1/4)y = y + 12
(6/12)y + (4/12)y + (3/12)y = y +12
(13/12)y - y = 12
(1/12)y = 12
y = 12*12 = 144
The number is 144
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