the sum of one third of a number and 6 is 18 find the number pls help and do in a paper pls i beg u
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Step-by-step explanation:
Let us suppose the number is x.
Now, framing LHS : (x/3) + 16 ________ (1)
Framing RHS : 3x _______ (2)
Therefore, ATP,
(x/3) + 16 = 3x
=> x + 48 = 9x ________ (Multiplying both sides by 3)
=> 9x - x = 48
=> 8x = 48
=> x = 6 _______ (Dividing both sides by 8)
Therefore, the required no. is 6 _______ (Ans: )
Cross-check : LHS -> (6/3) + 16 = 18
RHS -> 3*6 = 18
Therefore, LHS = RHS _______ (Hence proved )
Hope it helps ! :-)
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