The sum of opposite angles of a parallelogram is 100◦. Find all the angles of the parallelogram.
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ABCD is a parallelogram.
∠B+∠D=130∘
∠B=∠D (opposite angles of a parallelogram are equal)
∠B=∠B=130∘
2∠B=130∘
b = {130}{2}
∠B=65∘
Now ∠B+∠C=180∘ (adjacent angles of a parallelogram are supplementary )
∠C=180∘−∠B=180∘−65∘
∠C=115∘
∴∠A=∠C=115∘ (opp. angles of parallelogram are equal)
∴∠B=∠D=65∘ and ∠A=∠C=115∘
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