Math, asked by subhasinisubbu22, 5 hours ago

the sum of present age in a father and son is 60 years six years ago, the father's age was five times the age of his son. after 6 years, the son's age will be​

Answers

Answered by rosesharma2323
0

20

Step-by-step explanation:

Let the present age of son be x.

Then, present age of father is (60−x).

According to the question,

⇒ (60−x)−6=5(x−6)

⇒ 54−x=5x−30

⇒ 54+30=5x+x

⇒ 84=6x

⇒ x= 84/6

⇒ x=14

∴ Son's age after 6 years =(x+6)years

=(14+6)years

=20years.

Answered by SHUBHMALHOTRA
5

 \Large\bf \underline\purple{Answer }

  • Let take present age to be (X)
  • Then, the present age of his father is given as = (60-x)

 \Large\bf\underline\green{According \: to \: the \: question}

  • ⇒(60-x) - b = 5 (X-6)
  • 54 - x = 5x-30
  • 54 + 30 = 5x+x
  • 84 = 6x

 \small\bf\underline\pink{⇒X  \: = \: 84/6   }

 \small\bf\underline\pink{⇒ \: x  \:  = 14  }

  • Son after 6 Year .= (X+6) years
  • (14+6) Years

\small\bf\underline\blue{⇒20 \: year   }

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