Question

the sum of present ages of 3 friends is 90 years if before 10 years their ages were in the ratio of 1:2:3 find their ages​

Answer 1

Answer:

Step-by-step explanation:

Let their ages 10 years ago is x, 2x and 3x years.

10 + 2x + 10 + 3x + 10 = 90 hence x= 10

B’s present age = (2x + 10) =30 years

Answer 2

Step-by-step explanation:

Ages 10 years before = x,2x,3x

Present Ages=x+10,2x+10,3x+10

x+10+2x+10+3x+10=90

6x+30=90

6x=60

x=10

Present Ages=x+10,2x+10,3x+10=20,30,40