Math, asked by deepika6312, 11 months ago

The sum of present ages of A and B ÍS 11 times the difference of their ages.
5 years hence their total ages will be 13 times the difference of their ages. What
is the present age of elder one?
a) 35 (b) 20 (c) 25 (d) 30 (e) None​

Answers

Answered by neetutosonu
4

Answer:

As per given condition

a+b=11(a-b)

a+b=11a-11b

12b=10a      ....1

5 yrs hence a's age will be a+5

and b's age will be b+5

Again

a+5+b+5=13(a-b)

a+b+10=13a-13b

12a-14b=10 .....2

On solving eq 1&2

a=30

b=25

Thus the elder one's age is 30 Option:d

Answered by gargpriya0114
1

Answer:

The present age of elder one is 30.

Step-by-step explanation:

A + B = 11 ( A- B )

or , A + B = 11A - 11B.

or , 10A = 12B.

or , 5A - 6B = 0 .

After 5 years ,

A + 5 + B + 5 = 13 ( A - B)

or ,  A + B + 10 = 13A - 13B .

or , 12A - 14B = 10

or , 6A - 7B = 5.

35A - 42B = 0....... (I)

36A - 42B = 30..... (II)

I-II

-A = -30.

or , A = 30.

The present age of elder one is 30.

#SPJ2

Similar questions