Math, asked by itsme9523, 7 months ago

The sum of present ages of A and B is 58 years. 5 years hence A's age will be 3 times that of B's age. What are their present ages?

Answers

Answered by hassans17
0

Answer:

46, 12

Step-by-step explanation:

A + B = 58

A + 5 = 3(B+5)

A = 3B + 10

Therefore, 58-B = 3B +10

4B = 48, so B = 12

A = 46

Answered by Eutheria
0

Answer:

A=46 years

B=12 years

Step-by-step explanation:

a+5=3(b+5)

a-3b=10. (i)

a+b=58. (ii)

substraction of both eq.

-4b=-48

b=12 years

a=46 years

Similar questions