Question

The sum of present ages of A and B is 68 years. 2 years hence A's age will be 3 times that of B's age. What are their present ages?

Answer 1

Answer:

Step-by-step explanation:

Let present age be x of A and y of B

x+y = 68

2 yrs later,

A's age=x+2

B's age= y+2

A/q, x+2 = 3(y+2)

        68-y+2= 3y+6

         70-6 = 4y

          64 = 4y

           y = 16

x= 68-16

    = 52

Answer 2

Answer:

The present ages of A and B are 52 years and 16 years respectively.

Step-by-step explanation:

Let the present ages of the two be: A and B

So, we have A+B = 68 years

After 2 years:

A+2 = 3( B+2)

So, we can write it as : (68-B) + 2 = 3( B+3)

Or, 70-B = 3B+ 6

Or, 4B = 64

Or B = 64/4 = 16 years

Hence, A = 68-16 = 52 years.