Question

The sum of present ages of a father and his son is 80 years. When the father's age was equal to the present age of the son, the sum of their ages was 40 years. Find their present ages.​

Answer 1

Answer:

Father's present age = 50 years

Son's present age = 80 - 50 =30 years

Step-by-step explanation:

Let,

father's present age = x

son's present age = 80-x

Some t years ago, we know that father's age was equal to son's present age,

x-t=80-x collecting like terms we have:

2x-t=80---------------(1)

At that time, we also know that son's age was (80-x)-t

Now we are told that:

x-t+(80-x)-t=40, simplifying, we get

-2t+80=40

-2t=-40 or

t=20 , substituting t=20 into eq1, we have

2x-20=80

2x=100

x=50 -----------father's present age

80-x=80-50=30-----------son's present age

CK

50+30=80

80=80

and

(50-20)+(30-20)=40

40=40

Therefore,

Father's present age = 50 years

Son's present age = 80 - 50 =30 years