Question

the sum of present ages of a father and his son is 80 years . when the fathers age was equal to the present age of the son the sum of their ages was 40 years find present age​

Answer 1

Answer:

Father's present age = 50 years

Son's present age = 80 - 50 =30 years

Step-by-step explanation:

Let,

father's present age = x

son's present age = 80-x

Some t years ago, we know that father's age was equal to son's present age,

x-t=80-x collecting like terms we have:

2x-t=80---------------(1)

At that time, we also know that son's age was (80-x)-t

Now we are told that:

x-t+(80-x)-t=40, simplifying, we get

-2t+80=40

-2t=-40 or

t=20 , substituting t=20 into eq1, we have

2x-20=80

2x=100

x=50 -----------father's present age

80-x=80-50=30-----------son's present age

CK

50+30=80

80=80

and

(50-20)+(30-20)=40

40=40

Therefore,

Father's present age = 50 years

Son's present age = 80 - 50 =30 years

:)