the sum of present ages of Anil and his father is 54 years. six years before Anils father was six times as old as Anil find their present ages
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Let A be Anil's age and F be Anil's father's age.
A+F=54A+F=54
A=54−FA=54−F
And 6 years earlier, their respective ages were A−6A−6and F−6F−6.
F−6=6(A−6)F−6=6(A−6)
Substituting from above for A,
F−6=6(54−F−6)=6(48−F)=6∗48−6∗FF−6=6(54−F−6)=6(48−F)=6∗48−6∗F
F+6F=6∗48+6=6∗49F+6F=6∗48+6=6∗49
F=6∗497=42F=6∗497=42
A=54−F=54−42=12
A+F=54A+F=54
A=54−FA=54−F
And 6 years earlier, their respective ages were A−6A−6and F−6F−6.
F−6=6(A−6)F−6=6(A−6)
Substituting from above for A,
F−6=6(54−F−6)=6(48−F)=6∗48−6∗FF−6=6(54−F−6)=6(48−F)=6∗48−6∗F
F+6F=6∗48+6=6∗49F+6F=6∗48+6=6∗49
F=6∗497=42F=6∗497=42
A=54−F=54−42=12
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