Math, asked by satishpranjal09, 1 year ago

the sum of present ages of father and son is 68 years eight years ago, the ratio of their age was 12:1 ,what will be the ratio of their ages 4years hence​

Answers

Answered by erinna
4

The required ratio is 15:4.

Step-by-step explanation:

It is given that eight years ago the ratio of father and son age was 12:1.

Let eight years ago the age father and son are 12x and x respectively.

Present age of father = 12x+8

Present age of son = x+8

The sum of present ages of father and son is 68 years.

12x+8+x+8=68

13x+16=68

13x=68-16

13x=52

Divide both sides by 13.

x=4

Present age of father = 12(4)+8 = 56

Present age of son = 4+8 = 12

The ratio of their ages 4 years hence​ is

\dfrac{56+4}{12+4}=\dfrac{60}{16}=\dfrac{15}{4}=15:4

Therefore, the required ratio is 15:4.

#Learn more

The sum of the present ages of father and son is 68 years. eight years ago, the ratio of their age was 12:1. what will be the ratio of their ages 4 years hence​.

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