Math, asked by savitagupta20008, 3 months ago

the sum of product of zeroes taken two at time of polynomial f(x)=x^3-5x^2+3x+4 is​

Answers

Answered by amishacares
2

Step-by-step explanation:

ax^3+bx^2+cx+d

sum of product of zeroes taken two at a time=c/a

ATQ,

sum of product of zeroes taken two at a time=3

Answered by khushi814752
0

Answer:

  1. x2 - 2x - 8 = x2 - 4x + 2x - 8 = x(x - 4) + 2(x - 4) = (x - 4)(x + 2) The zeroes of the quadratic equation are 4 and -2. Let ∝ = 4 and β = -2 Consider f(x) = x2 - 2x - 8 Sum of the zeroes = …(i) Also, ∝ + β = 4 - 2 = 2 …(ii) Product of the zeroes = …(iii) Also, ∝ β = -8 …(iv) Hence, from (i), (ii), (iii) and (iv),the relationship between the zeroes and their coefficients isverified
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