the sum of q term of an Ap is 162.the ratio of ots 6 th term to its 13 th term is 1:2.find the first and 15 th term of AP
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T6/T13 = (a+5d)/(a+12d) = 1/2
solving that : a = 2d
sum of 9 terms = 162
9/2 * (2a + 8 d) = 162
12 d = 36 => d = 3, a = 6
first term = 6, 15th term = 6 + 14*3 = 48
solving that : a = 2d
sum of 9 terms = 162
9/2 * (2a + 8 d) = 162
12 d = 36 => d = 3, a = 6
first term = 6, 15th term = 6 + 14*3 = 48
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