The sum of q terms of an A.P IS 162.The ratio of the sixth term and the 10th term is 1:2. Find the first and the 15th term of this A.P.
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ratio = (a+5d) / (a+ 9d) = 1/2
=> a + d = 0 => a = -d
sum of 9 terms = 162
9/2 * (2a + 8 d) = 162
6d = 36
d = 6
a = -6
first term = -6, T15 = -6 + 14*6 = 78
=> a + d = 0 => a = -d
sum of 9 terms = 162
9/2 * (2a + 8 d) = 162
6d = 36
d = 6
a = -6
first term = -6, T15 = -6 + 14*6 = 78
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