Question

The sum of radii of two circles is 17 cm and the difference of
circumferences is 44 cm. Find the two radii.
​

Answer 1

$\huge{\bf{\underline{\underline{AnSwEr:-}}}}$

$\large\sf\therefore\green{r_1= 12cm \: and \: r_2= 5cm }$

$\large{\sf{\underline{\underline{Given:-}}}}$

•$\large\bf\ r_1+r_2= 17cm$

•$\large\bf\ 2πr_1-2πr_2 = 44cm$

$\large{\sf{\underline{\underline{To \: find:-}}}}$

•$\large\bf\ r_1 \: and \: r_2$

$\large{\sf{\underline{\underline{SoluTion:-}}}}$

$\large\tt\to\ r_1+ r_2 = 17 ----->(eq.1) \\ \\ \large\tt\to\ 2πr_1- 2πr_2 =44 \\ \\ \large\tt\to\ 2π(r_1 - r_2) =44 \\ \\ \large\tt\to\ 2 \times\frac{22}{7}(r_1-r_2)=44 \\ \\ \large\tt\to\ (r_1-r_2) = \frac{ 44 \times\ 7}{ 2 \times\ 22} \\ \\ \large\tt\to\ (r_1-r_2) = 7-----(eq.2)$

$\large\sf\therefore\purple{By \: using \: eq.1 \: and \: eq.2 \: We \: get;}$

$\large\tt\to\ 2r_1= 24 \\ \\ \large\tt\to\ r_1= \frac{24}{2}= 12$

$\large\sf\therefore\purple{ Putting \: the \: value \: of \: r_1 \: in \: eq.1}$

$\large\tt\to\ r_1-r_2 =17 \\ \\ \large\tt\to\ 12-r_2 =17 \\ \\ \large\tt\to\ r_2 =17-12 \\ \\ \large\tt\to\ r_2= 5$

Answer 2

Hope it helps you.... (✿❛◡❛)ヾ(❀╹◡╹)ﾉﾞ