Math, asked by basusurajit63, 2 months ago

the sum of raju's age and half of sameer's age is 4 one third raju's age added to twice sameer's age is 5 find the sum of their ages

Answers

Answered by AestheticSoul
2

Given :

• Sum of Raju's age and half of Sameer's age = 4

• One third of Raju's age added to twice Sameer's age = 5

To find :

• Sum of their ages

Solution :

Let us assume the present age of Raju and Sameer be x and y respectively.

According to the first condition given in the question,

→ Sum of Raju's age and half of Sameer's age = 4

→ x + ½ × y = 4

→ x + y/2 = 4

→ (2x + y)/2 = 4

→ 2x + y = 8 -----(1)

According to the second condition given in the question,

→ One third of Raju's age added to twice Sameer's age = 5

→ ⅓ × x + 2 × y = 5

→ x/3 + 2y = 5

→ (x + 6y)/3 = 5

→ x + 6y = 15 -----(2)

Solve (1) and (2) :-

→ (2x + y = 8) × 1

→ 2x + y = 8 -------(3)

→ (x + 6y = 15) × 2

→ 2x + 12y = 30 -----(4)

Solving (3) and (4) :-

→ 2x + y = 8

→ 2x + 12y = 30

⠀(-)⠀(-)⠀⠀⠀(-)

______________

⠀⠀⠀- 11y = - 22

______________

→ - 11y = - 22

→ 11y = 22

→ y = 22/11

→ y = 2

The value of y = 2

Substitute the value of y in equation (1) :-

→ 2x + y = 8

→ 2x + 2 = 8

→ 2x = 8 - 2

→ 2x = 6

→ x = 6/2

→ x = 3

The value of x = 3

Therefore, the age of Raju and Sameer are :-

  • Age of Raju = x = 3 years
  • Age of Sameer = y = 2 years
Answered by paulkoshy
0

Let us assume the present age of Raju and Sameer be x and y respectively.

According to the first condition given in the question,

→ Sum of Raju's age and half of Sameer's age = 4

→ x + ½ × y = 4

→ x + y/2 = 4

→ (2x + y)/2 = 4

→ 2x + y = 8 -----(1)

According to the second condition given in the question,

→ One third of Raju's age added to twice Sameer's age = 5

→ ⅓ × x + 2 × y = 5

→ x/3 + 2y = 5

→ (x + 6y)/3 = 5

→ x + 6y = 15 -----(2)

Solve (1) and (2) :-

→ (2x + y = 8) × 1

→ 2x + y = 8 -------(3)

→ (x + 6y = 15) × 2

→ 2x + 12y = 30 -----(4)

Solving (3) and (4) :-

→ 2x + y = 8

→ 2x + 12y = 30

⠀(-)⠀(-)⠀⠀⠀(-)

______________

⠀⠀⠀- 11y = - 22

______________

→ - 11y = - 22

→ 11y = 22

→ y = 22/11

y = 2

The value of y = 2

Substitute the value of y in equation (1) :-

→ 2x + y = 8

→ 2x + 2 = 8

→ 2x = 8 - 2

→ 2x = 6

→ x = 6/2

x = 3

The value of x = 3

Therefore, the age of Raju and Sameer are :-

  • Age of Raju = x = 3 years
  • Age of Sameer = y = 2 years

Sum of their ages = 3+2

                              = 5

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