the sum of recipocal of consecutive odd natural number is 12÷35find those numbers plz
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HLW MATE!
LET, two consecutive odd natural number be X and X+2
So according to given condition
1/X+1/X+2=12/35
:SOLVING the equation simultaneously
:X+2+X/X^2+2X=12/35
:35(2X+2)=12(X^2+2X)
:70X+70=12X^2+24X
:divide equation by 2
:35X+35=6X^2+12X
:6X^2+12X-35X-35=0
:6X^2-23X-35=0
:6X^2-(30-7)X-35=0
:6X^2-30X+7X-35=0
:6X(X-5)+7(X-5)=0
:(6X+7)(X-5)=0
solve for X
X=-7/6 and 5
natural no can't be negative so X=5
AND TWO NUMBERS ARE 5 and 5+2=7
THANK U☺
LET, two consecutive odd natural number be X and X+2
So according to given condition
1/X+1/X+2=12/35
:SOLVING the equation simultaneously
:X+2+X/X^2+2X=12/35
:35(2X+2)=12(X^2+2X)
:70X+70=12X^2+24X
:divide equation by 2
:35X+35=6X^2+12X
:6X^2+12X-35X-35=0
:6X^2-23X-35=0
:6X^2-(30-7)X-35=0
:6X^2-30X+7X-35=0
:6X(X-5)+7(X-5)=0
:(6X+7)(X-5)=0
solve for X
X=-7/6 and 5
natural no can't be negative so X=5
AND TWO NUMBERS ARE 5 and 5+2=7
THANK U☺
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