The sum of reciprocals of rehman's ages 3 years ago and 5 years now is 1 by 3. Find his present age.
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Given:-
- The sum of reciprocals of Rehman's ages 3 years ago and 5 years now is 1 by 3.
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To find:-
- Find his present age.
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Solution:-
Let,
- the present age of Rehman be a.
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Here,
- Reciprocal of age of Rehman 3 years ago = 1/(a - 3) years.
- Reciprocal of age of Rehman 5 years from now = 1/(a + 5) years.
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According to the question
⇛ 1/(a - 3) + 1/(a + 5) = 1/3
⇛ (a + 5 + a - 3)/(a - 3)(a + 5) = 1/3
⇛ (2a + 2)/(a² + 2a - 15) = 1/3
⇛ 3(2a + 2) = a² + 2a - 15
⇛ 6a + 6 = a² + 2a - 15
⇛ a² + 2a - 15 - 6a - 6 = 0
⇛ a² - 4a - 21 = 0
⇛ a² - 7a + 3a - 21 = 0
⇛ a(a - 7) + 3(a - 7) = 0
⇛ (a + 3) (a - 7) = 0
⇛ (a + 3) = 0 or, (a - 7) = 0
⇛ a = -3 or, a = 7
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Hence,
- The present age of Rehman is 7 years.
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