Math, asked by priyasharma200, 1 year ago

The sum of reciprocals of two consecutive numbers is 23/132. Find the numbers.

Answers

Answered by Sahil4U
8
Let the Consecutive be x and x+1

Their reciprocal be 1/x+1/x+1


Their Sum = 23/132



1/x+1/x+1=23/132

LCM of x and x+1


1(x+1)+1(x)/x(x+1)=23/132

x+1+x/x²+x=23/132

2x+1/x²+x=23/132

Cross multiply

2x+1(132)=23(x²+x)

264x+132=23x²+23x

23x+23x-264x-132

23x-241x-132

(Factorise them and u will get ur answer)
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