Question

The sum of roots of a quadratic equation is 3 and the product of root is -28 . Find the quadratic equation ?

Answer 1

Answer:

${x}^{2} - 3x - 28 = 0.$

Step-by-step explanation:

$s = 3 \\ \\ p = - 28 \\ \\ equation \: is \: \: \: {x}^{2} - sx + p = 0 \\ \\ {x}^{2} - 3x - 28 = 0.$

Answer 2

Given,

Sum of roots $\[ = 3\]$

Product of roots $\[ = - 28\]$

Solution,

Consider the quadratic equation,

$\[{x^2} + \left( {sum\,of\,roots} \right)x + product\,of\,roots = 0\]$

$\[ \Rightarrow {x^2} + 3x - 28 = 0\]$

Hence the quadratic equation is $\[{x^2} + 3x - 28 = 0\]$