Question

The sum of roots of a quadratic equation is 9 and the sum of roots of their cube is 189. find the equation ​

Answer 1

Answer:

Step-by-step explanation:

a^3+b^3=189,a+b=9

$(a+b)^3=a^3+b^3+3ab(a+b)$

729=189+3ab(9)

540=27ab

20=ab

$(a-b)^2=(a+b)^2-4ab$

(a-b)^2=81-80

a-b=1.... eq 1

a+b=9.. eq2

sum the equation

2a=10

a=5

b=4

Answer 2

Answer:

41

Step-by-step explanation:

x+y=9

x*x*x*+y*y*y=189

consider values=1+8,2+7,6+3,4+5

The values are 4 & 5

4×4+5×5

=16+25

=41

Hope it helpful.......