Question

the sum of rs 12500 and interest rate is 4% per annum for 2 years compounded annually. find the compound interest.​

Answer 1

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Answer 2

$\bf \: \underline{ Given }\: :$ ↴

$\sf \implies Principal = Rs. \:12500$

$\sf \implies Rate \: of \: Interest = 4 \: \%$

$\sf \implies Time =2\: Years.$

$\bf \: \underline{To \: find }\: :$ ↴

$\sf \implies Compound \: Interest$

$\bf \: \underline{\underline{Solution } }$

$\sf \: First \: of \: all \: we \: have \: to \: find \: the \: amount.$

$\sf \implies{ \boxed{ \red{ \sf \: Amount \: : P \: \bigg(\: 1 + \frac{R}{100} \: \bigg ) ^{n} }}}$

$\bf \: \underline{Putting \: the \: values},$

$\sf \implies 12500 \: \bigg(\: 1 + \dfrac{4}{100} \bigg ) ^{2}$

$\sf \implies 12500 \: \bigg(\: 1 + \dfrac{1}{25} \bigg ) ^{2}$

$\sf \implies 12500 \: \bigg(\: \dfrac{25 + 1}{25} \bigg ) ^{2}$

$\sf \implies 12500 \: \bigg(\: \dfrac{26}{25} \bigg ) ^{2}$

$\sf \implies 12500 \: \times \: \dfrac{676}{525}$

$\sf \implies 20 \times 676$

$\purple{\sf \implies Amount = Rs. \: 13520}$

$\sf \: Now, we \: will \: find \: the \: Compound \: Interest.$

$\sf \implies{ \boxed{ \sf \red{CI = Amount \: - Principal }}}$

$\sf \implies { {CI = 13520 - 12500}}$

$\sf \implies { {CI = Rs. \:1020}}$

$\underline{ \boxed{ \purple{{ \sf {Hence, the\:compound \: Interest \:is\: Rs. \: 1020}}}}}$