Question

the sum of rupees 3200 invested at 10% per annum compound amount to rupees 3362 rupees calculate the time period

Answer 1

3362=3200(1+10/100)^n
3362/3200=(11/10)^n
1681/1600=(11/10)^n
worng amount

Answer 2

Question : The sum of Rs. 3200 invested at 10% per annum compounded quarterly amounts to Rs. 3362. Calculate the time period.

$\fbox{ANSWER} \\ \\ \implies Given,\ P=Rs.\ 3200 \\ R=10\%\ per\ annum\ = \frac{10}{4}\%\ quarterly \\ T= ? \\ A=Rs.3362 \\ \\ 3362=3200 \bigg(1+\frac{10}{400}\bigg)^n \\ \\ \implies\frac{3362}{3200}=\bigg(\frac{410}{400}\bigg)^n \\ \\ \implies \frac{1681}{1600}=\bigg(\frac{41}{40}\bigg)^n \\ \\ On\ comparing\ both\ sides,\ we\ get \\ \\ \bigg(\frac{41}{40}\bigg)^2 = \bigg(\frac{41}{40}\bigg)^n \\ \\ \implies n=2 \\ \implies T=2\ quarter\ year \\ \implies T=2 \times3=6\ months \big(1\ quarter\ year=3\ months \big)$