Question

The sum of rwo integers is 2 and their product is -48 then find the integers

Answer 1

Answer:

then two integers are -6 and 8

Step-by-step explanation:

let the integers = x and y

x + y = 2 ------(1)

xy = -48 ------(2)

from eq 1

x + y = 2

x = y - 2

put x in eq 2

xy = - 48

(2 - y)y = - 48

2y -y² = -48

-y² + 2y + 48 = 0

on multiply by -1

y² - 2y - 48 = 0

y² - (8 - 6)y - 48 = 0

y² - 8y + 6y - 48 = 0

y(y - 8).+6(y - 8) = 0

(y + 6)(y - 8) = 0

y + 6 = 0 , y - 8 = 0

y = -6 , y = 8

if y = -6 then x is..

x + y = 2

x + (-6) = 2

x - 6 = 2

x = 6 + 2

x = 8

if y = 8 then x is

x + y = 2

x + 8 = 2

x = 2 - 8

x = -6