The sum of series 1/V3+1+3/V3+.... to 18 terms is
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Answer:
19682/(17√3)
Step-by-step explanation:√ × ≈ ÷
This is a geometric progression with a1=1/√3, r=√3, n=18
Using the formula Sn=a1(r^n - 1)/(r-1), we get
S18=(1/√3){√3^18 - 1}/(18-1)
= (3^9 - 1)/(17√3)
= (19683 - 1)/(17√3)
= 19682/(17√3)
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