Question

the sum of series 4/7-5/7^2+4/7^3-5/7^4.......

to infinitely many terms is equal to

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Answer 1

Answer:

here is the answer

4/7+4/7^3 +4/7^5.......=S1

-5/7^2-5/7^4-5/7^6....=S2

S1=4/7(1+1/7^2+1/7^4...)

S1=4×49/48×7

S1=7/12

S2=-5/7^2(1+1/7^2+1/7^4...)

S2=-5×49/48×49

S2=-5/48

S1+S2=23/48

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