Question

The sum of series $\frac{1}{2!}+\frac{1}{4!}+\frac{1}{6!}+......$ is
(a) $\frac{(e^{2}-2)}{e}$
(b) $\frac{(e-1)^{2}}{2e}$
(c) $\frac{(e^{2}-1)}{2e}$
(d) $\frac{(e-1)^{2}}{2}$

Answer 1

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