Question

The sum of six consecutive even numbers of set-a is 402. what is the sum of another set-b of four consecutive numbers whose lowest number is 15 less than double the lowest number of set-a?

Answer 1

SET-A
let the first no. = x
secind no.=x+2
third no.=(x+2)+2
=x+4
fourth no.=(x+4)+2
=x+6
fifth no.=(x+6)+2
=x+8
sixth no.=(x+8)+2
=x+10

sum of the no.s = 402
x+(x+2)+(x+4)+(x+6)+(x+8)+(x+10)=402
x+x+2+x+4+x+6+x+8+x+10=402
6x+30=402
6x=402-30
6x=372
x=372 / 6
x=62

first no. =x
=62
second no.=x+2
=62+2
=64
third no.=x+4
=62+4
=66
fourth no.=x+6
=62+6
=68
fifth no.=x+8
=62+8
=70
sixth no.=x+10
=62+10
=72

SET-B