Question

The sum of sixteen consecutive even integers is 544. Then the difference between second one and
second last one is

Answer 1

Answer:

You have given us

∑n=18x+2n=456

but

∑n=916x+2n=

∑n=18x+2(n+8)=

∑n=18x+2n+16=

128+∑n=18x+2n=

Answer 2

QUESTION⇩⇩

The sum of sixteen consecutive even integers is 544. Then the difference between second one and second last one is?

ANSWER⇩⇩

26

GIVEN THAT⇢

n=16

d=2

S16=544

TO FIND⇢

a=?

FORMULA USED⇢

$\frac{n}{2} [2a+(n-1)d]=Sn$

LET'S DO IT⇢

$\frac{16}{2} [2a+15 \times 2]=544$

$2a+30=68$

$2a=38$

${ \boxed{ \underline{ \pink{a=19}}}}$

now,

2nd term is, a+d

= 19+2

=21

2nd last term is,

a+14d

a+14d

=19+28

=47

difference between 2nd term and second last term is

$= 47-21=26$

${\boxed{\underline{\purple{26}}}}$

$\dag\orange{HOPE \: \: IT \: \: HELPS}\dag$