Physics, asked by shrishakanlat1998, 19 hours ago

The sum of square of auxiliary operators is​

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Answered by neerajgopalv
0

Answer: Sum of squares of differences between all pairs of an array

Difficulty Level : Hard

Last Updated : 29 Jan, 2022

Given an array arr[] of size N, the task is to compute the sum of squares of differences of all possible pairs.

Input: arr[] = {2, 8, 4}

Output: 56

Explanation: Sum of squared differences of all possible pairs = (2 – 8)2 + (2 – 4)2 + (8 – 4)2 = 56

Input: arr[] = {-5, 8, 9, -4, -3}

Output: 950

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