Math, asked by Reen92, 1 year ago

The sum of square of first n natural number is_
(A) (n/2)(n+1) (B) (n/6)(n+1)(2n+1) C)
The sum of cubes of first n natural number is_.
(A) (n/2)(n+1) (B) (n/6)(n+1)(2n+1) (C) (

Answers

Answered by Lallermani
0
1 a)
2 b) these are the answers of mcqs
Answered by mysticd
3

Solution:

i) The sum of square of first n natural number is_

[n(n+1)]/2

Option (A) is correct.

ii)The sum of cubes of first n natural number is_.

{[n(n+1)]/2}²

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