Question

the sum of square of three consecutive positive integers is 110 . find the integer

Answer 1

Answer:

let the first integer be x

then second integer is x+1

and third integer is x+2

(x²)+(x+1)²+(x+2)²=

x²+x²+1+2*x*1+x²+4+4x=110

x²+x²+1+2x+x²+4+4x=110

3x²+6x+5=110