Question

The sum of square of three positive integer is 323. if the sum of square of two number is twice the third, find the product of the number

Answer 1

Let the integers be

a,b,c

split the 323 in to their squares

a = 5

b = 3

c = 17

So, a2+b2+c2=323

and

a2+b2=2c

252+32=2×17

34=34

So

a : b : c = 17×5×3=255