the sum of square of two consecutive natural no is 244.find number
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Let the two natural numbers be
x and x+1
Given:
x^2 +(x+1)^2 =244.
Now,
9^2+10^2= 81 + 100 = 181
10^2+11^2 = 100 + 121 = 221
11^2+12^2 = 121 + 144 = 265.
There are no two consecutive natural
numbers whose sum of squares is 244.
I hope this answer help you
x and x+1
Given:
x^2 +(x+1)^2 =244.
Now,
9^2+10^2= 81 + 100 = 181
10^2+11^2 = 100 + 121 = 221
11^2+12^2 = 121 + 144 = 265.
There are no two consecutive natural
numbers whose sum of squares is 244.
I hope this answer help you
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