Question

The sum of square of two consecutive natural number is 244 . find the numbers ​

Answer 1

$\sf \purple{hello \: friend \: here \: is \: your \: answer : } \\ \sf{ {x}^{2} + (x + 1) {}^{2} = 244 } \\ \sf{ {x}^{2} + {x}^{2} + 1 + 2x = 244} \\ \sf{2 {x}^{2} + 2x + 1 = 244} \\ \sf{2 {x}^{2} + 2x = 243} \\ \sf{2 {x}^{2} + 2x - 243 = 0 } \\ \sf \green{solve \: the \: following \: equation \: and \: you \: will \: get \: the \: answer}$

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