Question

The sum of square of two consecutive natural odd number is 202. What is the mathematical form of a statement?( Use on variable)​

Answer 1

Answer:

Let two consecutive odd numbers be x and x+2

Let two consecutive odd numbers be x and x+2x

Let two consecutive odd numbers be x and x+2x 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2)

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=202

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x 2

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x 2 +11x−9x+9900

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x 2 +11x−9x+9900(x−9)(x+11)=0,x=9,−11

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x 2 +11x−9x+9900(x−9)(x+11)=0,x=9,−11-11 is not possible

Let two consecutive odd numbers be x and x+2x 2 +(x+2) 2 =202,x 2 +x 2 +4+4x=2022x 2 +4x+4=202,x 2 +11x−9x+9900(x−9)(x+11)=0,x=9,−11-11 is not possiblex=9,x=9+2=11

Answer 2

Answer:

2x^2+2x+1=202

Step-by-step explanation:

let the two consecutive odd natural numbers be x and x+1.

(x)^2+(x+1)^2=202

x^2+x^2+1^2=202

2x^2+1^2=202

2x^2+1=202