Question

the sum of square of two consecutive numbers is 244 . find the number
​

Answer 1

Step-by-step explanation:

let number be a

then a²+ (a+2)²=244

a²+a²+4a+4=244

2a²+4a+4-244=0

2a²+4a-240=0

a²+2a-120

x= (-b±√b²-4ac)/2a

a=(-2±√(4+480))/2

a=-2±22/2

a=22-2/2 and a=-22-2/2

a=20/2 and a=-24/2

a=10 and a=-12

two consecutive number may be 10 and12 or -10 and -12

Answer 2

Step-by-step explanation:

hope it will be help you...