The sum of square of two consecutive odd number is 514 . Find those numbers
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15 and 17 are the numbers
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Let the two consecutive odd numbers be x and x+2.
Given that sum of squares of two consecutive odd numbers is 514.
x^2 + (x+2)^2 = 514
x^2 + x^2 + 4x + 4 = 514
2x^2 + 4x = 510
x^2 + 2x = 255
x^2 + 2x - 255 = 0
x^2 - 15x + 17x - 255 = 0
x(x-15) + 17(x - 15) = 0
(x+17)(x-15) = 0
x = 15,-17.
if x = 15 then x + 2 = 17.
if x = -17 then x + 2 = -15
Hope this helps!
Given that sum of squares of two consecutive odd numbers is 514.
x^2 + (x+2)^2 = 514
x^2 + x^2 + 4x + 4 = 514
2x^2 + 4x = 510
x^2 + 2x = 255
x^2 + 2x - 255 = 0
x^2 - 15x + 17x - 255 = 0
x(x-15) + 17(x - 15) = 0
(x+17)(x-15) = 0
x = 15,-17.
if x = 15 then x + 2 = 17.
if x = -17 then x + 2 = -15
Hope this helps!
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