The sum of square of two consecutive odd numbers is 202. Find the numbers
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Answered by
4
Let the no. be x, x+2
ATQ
(x)^2+(x+2)^2=202
2x^2+4x+4-202=0
2x^2+4x-198=0
Divide by 2 & then split it
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Answered by
18
let the no be x and x+2
x² +(x+2)² =202
x² + x² + 4x +4 =202
2x²+4x-198 =0
2(x²+2x-99)=0
x²+11x-9x-99=0
x(x+11)-9(x+99)=0
(x+99)(x-9) =0
x=-99 0r 9
x² +(x+2)² =202
x² + x² + 4x +4 =202
2x²+4x-198 =0
2(x²+2x-99)=0
x²+11x-9x-99=0
x(x+11)-9(x+99)=0
(x+99)(x-9) =0
x=-99 0r 9
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