Question

The sum of square of two positive number is greater than their products by 28.if the ratio of the numbers is 2:3
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Answer 1

The numbers are in the ratio 2:3

So let us assume one number to be 2x and other to be 3x

Sum of their squares is 28 greater than their product.

Let us write that down as an equation.

(2x)² + (3x)² = 6x² + 28

13x² = 6x² + 28

7x² = 28

x² = 4

x = ±2

Given that the numbers are positive, we reject the negative value.

So x = 2

So the numbers are 4 and 6.