Question

The sum of square of two positive numbers is 628 and one number is 45(5/11)% less than other number.Find the smaller one

Answer 1

Answer:12

Step-by-step explanation:

let one number - x

Second number is 45 (5/11) % less than first one .

45 (5/11)% = 5/11 so second number is 6x/11.

x^2 + (6x/11)^2= 628

x= 22 .

Second number = 6×22/11=12