The sum of square two consecutive odd numbers is 394 . Find them
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Let the numbers be x and (x + 2)
• According to the Question :
⇒ x² + (x + 2)² = 394
⇒ x² + x² + 4x + 4 = 394
⇒ 2x² + 4x - 390 = 0
⇒ x² + 2x - 195 = 0
⇒ x² + 15x - 13x - 195 = 0
⇒ (x + 15)(x - 13) = 0
⇒ x = 13
• Required Numbers :
◗ x = 13
◗ (x + 2) = 13 + 2 = 15
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